School of Engineering · Playlist

Units, Motion, and Force

Measurement language, conversions, motion, acceleration, geometry, mass, and force for engineering work.

  1. Measurement Language
  2. Dimensional Analysis
  3. Motion Quantities
  4. Acceleration and Squared Time
  5. Geometry, Mass, and Force
Engineering Fundamentals/Units and Measurement

Measurement Language

Use quantities, units, symbols, and SI prefixes precisely before a drawing, program, or calculation has a chance to drift.

A measurement is a number and a unit

A measurement is a number and a unit

A dimension on a drawing, a speed in a robot program, and a torque setting are all quantities: a number paired with a unit. The number tells how many; the unit tells what kind of thing and how large each part is.

25 mm
A length: twenty-five millimeters. Writing only 25 leaves the measurement incomplete.
4.25 min
A CNC cycle time. It is not interchangeable with 4.25 seconds or 4.25 hours.
3.0 m/s
A speed or velocity magnitude. The slash means meters per second.

Carry units through every line of a calculation. They are an error check, not decoration. If the last line needs a length and the units say seconds, stop before the wrong number reaches a drawing or controller.

Use the unit symbol exactly as specified: m for meter, s for second, kg for kilogram. Symbols are not pluralized and do not take a period: 12 mm, not 12 mms.

Two systems you will encounter

Two systems you will encounter

The International System of Units (SI) is the standard system for science and much technical work. U.S. drawings, hardware, materials, and equipment also use U.S. customary units. Neither system lets us skip the unit; the job is to state which one is being used and convert deliberately when they meet.

SI drawing 25.0 mm millimeters
The same machined plate measured in two unit systems A rectangular plate is dimensioned across the same width. One drawing calls it 25 millimeters and the other calls it about 0.984 inches.
U.S. customary drawing ≈ 0.984 in inches
The part does not change. The measurement language does. A value copied without its unit can make the same feature look like two different sizes.
SI base units used here
meter (m) for length, second (s) for time, and kilogram (kg) for mass.
U.S. customary units used here
inch (in), foot (ft), mile (mi), second (s), pound mass (lbm), and U.S. liquid gallon (U.S. gal).
Coherent BG engineering system
The source slides call the coherent engineering form BG (British Gravitational): foot, slug, and second. In that system, slug · ft/s2 = lbf. A pound force and a pound mass are not the same unit.

A gallon must be named. This unit set uses the U.S. liquid gallon (U.S. gal), not an Imperial gallon.

Supporting detail: Addendum 1 — Why technical writing cares about the space.

SI prefixes change scale, not quantity

SI prefixes change scale, not quantity

A prefix is a power of ten attached to a unit. It makes a practical-sized number without changing the physical quantity: 0.025 mm and 25 µm describe the same length.

Common engineering prefix ladder Move right: each unit is 1,000 times smaller, so the number is 1,000 times larger.
  1. kilokm103 m
  2. no prefixm100 m
  3. millimm10−3 m
  4. microµm10−6 m
  5. nanonm10−9 m

1 m1,000 mm 1,000,000 µm1,000,000,000 nm

The ladder is a teaching subset; the complete reference follows. It shows why 1 mm = 0.001 m and 1 µm = 0.000001 m: changing a prefix changes the number used to describe a length, not the length itself.
All current SI prefixes, plus the unprefixed unit used between them.
NameSymbolFactor
quettaQ1030
ronnaR1027
yottaY1024
zettaZ1021
exaE1018
petaP1015
teraT1012
gigaG109
megaM106
kilok103
hectoh102
decada101
none—100
decid10−1
centic10−2
millim10−3
microµ10−6
nanon10−9
picop10−12
femtof10−15
attoa10−18
zeptoz10−21
yoctoy10−24
rontor10−27
quectoq10−30

Case matters. M is mega (106); m is milli (10−3). A wrong capital letter changes a result by a billion.

Prefix explorer

Prefix explorer

Choose two prefixes for the same base unit. The calculation compares their powers of ten; it does not change what is being measured.

Convert one prefixed meter value

Move 3 powers toward larger units. The target unit is 103 times larger, so the numerical value is divided by 103.

Result: 0.025 mm

25 µm = 25 × 10−6 m = 0.025 × 10−3 m = 0.025 mm.

Practice and sources; Practice

Practice and sources

Use the practice bank to apply this lesson’s prefix-conversion method.

Add to practice

Supporting detail: Addendum 2 — Sources and definitions.

Engineering Fundamentals/Units and Measurement

Dimensional Analysis

Convert quantities by multiplying by named equalities, cancelling units, and treating squared and cubed units as powers.

Convert by multiplying by one; Watch out

Convert by multiplying by one

A conversion factor is a ratio of two exactly equal physical quantities written as a fraction. For example, 1 ft and 0.3048 m name exactly the same length. Their ratio therefore has the numerical value 1, so multiplying by it changes the unit expression without changing the physical quantity.

Either orientation is valid: 1 ft / 0.3048 m and 0.3048 m / 1 ft both equal 1. Choose the orientation that cancels the unwanted unit. To convert 12 m to feet, put meters on the bottom:

12 m × = 39.370078740… ft ≈ 39.3701 ft.

For the reverse conversion, turn the same exact equality over so feet cancel:

39.370078740… ft × = 12 m.

Do not memorize an arrow. Write the desired unit, then arrange the factor so the unwanted unit cancels. The units tell you whether the fraction is facing the correct way before you calculate.

Exact, defined
1 in = 0.0254 m, so 1 ft = 0.3048 m and 1 yd = 0.9144 m exactly.
Keep guard digits
Use exact factors or sufficient digits while calculating; round the displayed result only at the end and only as the task needs.
Match dimensions
Length converts to length, area to area, volume to volume, and force to force. A calculator cannot make incompatible dimensions meaningful.
Powers apply to the whole conversion

Powers apply to the whole conversion

Area and volume are not lengths with decorative superscripts. The conversion factor itself must be squared or cubed.

Why a single linear factor is not enough.
QuantityExact relationshipUseful result
Length1 ft = 0.3048 m1 ft = 0.3048 m
Area(1 ft)2 = (0.3048 m)21 ft2 = 0.09290304 m2
Volume(1 ft)3 = (0.3048 m)31 ft3 = 0.028316846592 m3
Time squared(1 min)2 = (60 s)21 min2 = 3,600 s2

For example, 4 m2 × (1 ft / 0.3048 m)2 = 43.0556 ft2, which is sensibly reported as 43.1 ft2.

For liquid capacity, 1 m3 = 1,000 L and 1 U.S. gal = 3.785411784 L. The converter labels this as a U.S. liquid gallon so it cannot be mistaken for an Imperial gallon.

Supporting detail: Addendum 3 — Dimensional analysis is also a design check.

Conversion bench

Conversion bench

This tool uses exact internal factors where standards define them. It only converts within one quantity type; a length cannot become a speed without additional information.

Convert a quantity

Speed is a nonnegative magnitude and has no direction. A negative signed value represents a velocity component opposite the chosen positive direction.

Result: 39.3701 ft

12 m × (1 ft / 0.3048 m) = 39.370078740… ft ≈ 39.3701 ft.

CNC production calculation

CNC production calculation

A CNC program estimates 4 min 15 s per part. The operator uses 30 min of an 8 h shift for setup. How many complete parts fit in the shift?

  1. Convert the cycle: 4 min 15 s = 4.25 min.
  2. Find machine-running time: 8 h × (60 min / 1 h) − 30 min = 450 min.
  3. Divide running time by cycle time: 450 min / 4.25 min per part = 105.882....

105 complete parts. The fractional result is time into the 106th cycle, not a finished part. This assumes one machine, no unplanned stops, and that the stated cycle time already includes every repeatable operation.

Supporting detail: Addendum 4 — Two more conversion cases from the unit.

Practice and sources; Practice

Practice and sources

Use the practice bank to apply cubic conversion factors to a model volume.

Add to practice

Supporting detail: Addendum 5 — Sources and exact factors.

Engineering Fundamentals/Motion and Rotation

Motion Quantities

Distinguish path length from displacement, and speed from velocity, before using time to describe a machine or vehicle in motion.

Path length and displacement answer different questions

Path length and displacement answer different questions

Distance is how much path was traveled. Displacement is the directed change from the starting position to the ending position. A return trip can add distance while leaving displacement at zero.

Distance
A nonnegative scalar path length. A conveyor that moves a tote 12 m out and 12 m back travels 24 m of distance.
Displacement
A change in position with direction. If the tote returns to its start, its displacement is 0 m even though it moved.
Coordinate choice
Choose a positive direction before calculating. Along a straight robot rail, right might be positive and left negative.

Distance tells what the machine did along its path; displacement tells where it ended up relative to where it began. Do not substitute one for the other just because both use meters or feet.

Speed and velocity are not synonyms

Speed and velocity are not synonyms

Average speed is total distance divided by elapsed time. Average velocity is displacement divided by elapsed time. Velocity includes direction; speed does not.

average speed = total distance / elapsed time
average velocity = displacement / elapsed time

Notation bridge: this site uses x for position and Δx for displacement. Some course materials use s for position instead. For a stated interval, write average velocity as vavg = Δx / Δt; the symbols differ, but the physical idea is the same.

For the 12 m out-and-back path completed in 16 s, average speed is 24 m / 16 s = 1.5 m/s. Average velocity is 0 m / 16 s = 0 m/s. Both statements can be true at the same time.

A production-line example

A mechanism must carry a part 12 m in 8 s. Its required average speed is 12 m / 8 s = 1.5 m/s. Converting with exact factors gives 1.5 m/s × (39.37007874 in / 1 m) = 59.055... in/s, or 59.1 in/s. If the programmed direction is stated, its average velocity is +59.1 in/s in that direction.

Average and instantaneous readings

Average and instantaneous readings

An average uses a time interval. An instantaneous reading describes one moment: a car speedometer reports instantaneous speed; a robot controller’s live velocity value is an instantaneous velocity in its coordinate frame.

  • Use average speed for throughput, travel-time, and trip planning.
  • Use average velocity for a net movement over a stated interval.
  • Use an instantaneous reading when clearance, collision avoidance, or a machine limit depends on what is happening now.

Supporting detail: Addendum 6 — The calculus idea, after the practical one.

Out-and-back path lab

Out-and-back path lab

Set positions along a straight path and the outbound and return times. The text results make the distance and displacement distinction visible even when the track is not used.

Position and time inputs

Distance
24 m
Displacement
0 m
Average speed
1.5 m/s
Average velocity
0 m/s
Practice and sources; Practice

Practice and sources

Use the practice bank to apply distance, speed, and round-trip rate reasoning.

Add to practice

Supporting detail: Addendum 7 — Source note.

Engineering Fundamentals/Motion and Rotation

Acceleration and Squared Time

Calculate change in velocity over time, distinguish average from instantaneous acceleration, and convert squared time units correctly.

Acceleration is change in velocity over time

Acceleration is change in velocity over time

Acceleration is not simply “speeding up.” It is a change in velocity, so it can describe speeding up, slowing down, or turning.

aavg = Δv / Δt = (vf − vi) / (tf − ti)

Δv
Change in velocity. With one chosen positive direction, Δv = vf − vi.
m/s2
Meters per second per second. Each second, velocity changes by the stated number of meters per second.
ft/s2
Feet per second per second. The coherent foot–slug–second system uses this acceleration unit with slugs for mass.

Write the sign. A final velocity lower than the initial velocity produces negative acceleration in the selected direction; it is not an error just because the answer is negative.

Average is an interval; instantaneous is a moment

Average is an interval; instantaneous is a moment

Average acceleration is calculated over stated start and end conditions. An accelerometer or control system can report instantaneous acceleration at one moment. They match at every moment only when the acceleration stays constant through the interval.

Machine arm example

A machine arm starts from rest and reaches 3 m/s in 4 s:

aavg = (3 m/s − 0 m/s) / 4 s = 0.75 m/s2.

This is the average acceleration for the four-second move. If the drive ramps gently at the start and end, its instantaneous acceleration changes during the move even though the average remains 0.75 m/s2.

Robot gripper example

A SolidWorks motion study programs a gripper from 0 to 5 ft/s in 0.5 s to pick an electronic component. Its average acceleration is 5 ft/s / 0.5 s = 10 ft/s2. In SI, 10 ft/s2 × (0.3048 m / 1 ft) = 3.048 m/s2.

Squared time needs a squared factor; Watch out

Squared time needs a squared factor

Acceleration has time in the denominator twice. When converting an acceleration unit, convert the entire squared time relationship, not just one s.

1 min = 60 s means 1 min2 = (60 s)2 = 3,600 s2.

Use the inverse relationship in the correct direction. 1 ft/s2 = 0.3048 m/s2, not 0.30482 m/s2. The foot is the only unit being changed in that expression; seconds are already seconds in both units.

By contrast, converting m/min2 to m/s2 requires the full squared time factor. The unit cancellation shows why:

1 m/min2 × (1 min / 60 s)2 = 1/3,600 m/s2.

Acceleration lab

Acceleration lab

Change the initial and final velocities and the elapsed time. The last result converts the calculated foot-per-second-squared value to SI.

Velocity change

Change in velocity
5 ft/s
Average acceleration
10 ft/s²
SI equivalent
3.048 m/s²
Practice and sources; Practice

Practice and sources

Use the practice bank to apply average acceleration over a stated interval.

Add to practice

Supporting detail: Addendum 8 — Source note.

Engineering Fundamentals/Force and Power

Geometry, Mass, and Force

Scale CAD geometry correctly, connect volume and density to mass, and keep force and weight as separate quantities.

Scale changes area and volume by powers; Watch out

Scale changes area and volume by powers

If every linear dimension of a model is multiplied by a scale factor s, area changes by s2 and volume changes by s3. A 20% larger model is not 20% larger in area or volume.

Length
Lnew = sLold
Area
Anew = s2Aold
Volume
Vnew = s3Vold

For s = 1.2, area factor = 1.22 = 1.44 and volume factor = 1.23 = 1.728. This is why a modest scale change can matter to material use, shipping mass, tank capacity, and actuator selection.

Never scale an area with a linear factor or a volume with an area factor. The exponent belongs to the geometry, not to the number of decimal places.

Volume is capacity only after you name the unit

Volume is capacity only after you name the unit

CAD mass properties often report volume in a model’s document units. Before treating that number as a tank capacity or a material quantity, state the volume unit and convert it to the form the drawing or specification requires.

Volume relationships used in this unit.
RelationshipMeaning
1 m3 = 1,000 LA cubic meter contains one thousand liters.
1 U.S. gal = 3.785411784 LThis is a U.S. liquid gallon, not an Imperial gallon.
1 ft3 = 7.48051948 U.S. galDerived from the exact foot and U.S. gallon definitions.

Static solved reservoir example

A SolidWorks model gives a hydraulic reservoir internal volume of 2.5 ft3. Its capacity is 2.5 ft3 × 7.48051948 U.S. gal/ft3 = 18.7013 U.S. gal, or 18.7 U.S. gal. This assumes the reported CAD volume is the usable internal volume and no design headspace has yet been subtracted.

Density connects volume to mass

Density connects volume to mass

Density is mass per volume, and its symbol is ρ (rho): ρ = m/V. Turned around, when material density and CAD volume use compatible units, m = ρV produces mass.

(kg/m3) × (m3) = kg

Density units in the two systems.
SystemUnitConversion
SIkg/m31 kg/m3 = 0.00194032 slug/ft3
Foot–slug–secondslug/ft31 slug/ft3 = 515.3788 kg/m3

For example, a volume of 0.13824 m3 made of material with a density of 2,700 kg/m3 has mass m = 2,700 kg/m3 × 0.13824 m3 = 373.248 kg.

Static solved steel example

A steel I-beam has a volume of 0.2 m3 and a density of 7,850 kg/m3. Its mass is m = 7,850 kg/m3 × 0.2 m3 = 1,570 kg. That is the same mass the weight example below starts from — a CAD volume and a material card are usually where a weight calculation actually begins.

Mass does not change merely because an object is moved from one planet to another. Weight can change because gravitational acceleration changes. CAD models, material databases, and shipping specifications commonly need mass; lifting and support calculations commonly need force or weight.

Supporting detail: Addendum 9 — Check the CAD assumptions before trusting mass properties.

Force and weight are separate quantities

Force and weight are separate quantities

Force is a push or pull. For constant mass, Newton’s second law is Fnet = ma. Weight is one particular force: the force due to gravity, written W = mg.

Fnet
Net force, in newtons (N) or pound force (lbf). It is the combined force that produces acceleration.
W
Weight, a gravitational force. Near Earth’s standard gravity, g0 = 9.80665 m/s2; local gravity can differ slightly.
m
Mass, in kilograms, pound mass, or slugs. It is not measured in newtons or pound force.

In coherent SI, 1 N = 1 kg · m/s2. In the coherent foot–slug–second system, 1 lbf = 1 slug · ft/s2. Do not silently replace lbm with lbf.

Static solved weight example

For a 1,570 kg mass at standard gravity, W = mg = 1,570 kg × 9.80665 m/s2 = 15,396.44 N, or 15.4 kN. This is a weight calculation at standard gravity, not a claim that the mass is 15.4 kN.

CAD scale, mass, and weight lab

CAD scale, mass, and weight lab

This model begins with an area and volume in SI units, scales them, then uses density and gravitational acceleration to show the separate mass and weight results.

Model inputs

Area factor
1.44
Volume factor
1.728
Scaled area
1.8 m²
Scaled volume
0.13824 m³
Mass
373.248 kg
Weight force (N)
3660.3 N
Weight force (lbf)
822.9 lbf
Practice and sources; Practice

Practice and sources

Use the practice bank to apply squared-area conversion and complete-count reasoning.

Add to practice

Supporting detail: Addendum 10 — Sources and engineering context.

Supporting detail

Addendum

Additional evidence, standards context, and background referenced from the main text.

  1. Engineering Fundamentals/Units and Measurement/Measurement Language

    Addendum 1. Why technical writing cares about the space

    Leave a space between a numerical value and its unit symbol: 8 m, 15.0 kg, and 0.50 s. SI also uses a space before °C and %. Consistent notation is a low-cost way to keep a drawing, a spreadsheet, and a controller reading the same thing.

    Back to reference 1

  2. Engineering Fundamentals/Units and Measurement/Dimensional Analysis

    Addendum 3. Dimensional analysis is also a design check

    If a mass density is in kg/m3 and a CAD model volume is in m3, the cubic meters cancel and the result is kilograms. That is why CAD mass-property settings, material cards, and drawing units must be read together rather than as separate menus.

    Back to reference 3

  3. Engineering Fundamentals/Units and Measurement/Dimensional Analysis

    Addendum 4. Two more conversion cases from the unit

    Machine run time: an automated machine has operated for 15 years and 150 days. With the stated classroom assumption of 365 days per year, (15 × 365 + 150) d × (24 h / 1 d) = 135,000 h. Real maintenance records should use actual calendar dates and include leap days.

    Supply-chain fuel: a truck rated 15 mpg has 15 mi/U.S. gal × (1.609344 km / 1 mi) × (1 U.S. gal / 3.785411784 L) = 6.37716 km/L. A 150 km one-way route is a 300 km round trip, requiring 300 km / 6.37716 km/L = 47.0429 L, or 47.0 L, assuming the quoted fuel economy holds for the trip.

    Back to reference 4

  4. Engineering Fundamentals/Units and Measurement/Dimensional Analysis

    Addendum 5. Sources and exact factors

    The NIST SI Units reference documents SI base and derived units. The NIST conversion conventions define the inch as exactly 0.0254 m; this page derives square and cubic factors from that exact value. U.S. liquid gallon values are explicitly labeled whenever they are used.

    Back to reference 5

  5. Engineering Fundamentals/Motion and Rotation/Motion Quantities

    Addendum 6. The calculus idea, after the practical one

    Over a smaller and smaller time interval, average velocity approaches instantaneous velocity. In calculus notation, velocity is the derivative of position with respect to time: v = dx/dt. For this course, begin by naming the interval, position change, and direction correctly; the derivative notation is a compact extension of the same idea.

    Back to reference 6

  6. Engineering Fundamentals/Motion and Rotation/Motion Quantities

    Addendum 7. Source note

    The NIST SI Units reference lists velocity as a derived unit example. Direction is an added physical requirement: two motions may have the same speed but different velocities because their directions differ.

    Back to reference 7

  7. Engineering Fundamentals/Force and Power/Geometry, Mass, and Force

    Addendum 9. Check the CAD assumptions before trusting mass properties

    Confirm the assigned material, density, document unit, bodies included, and whether the model represents solid material or an internal void. A precise calculation based on the wrong material card is still wrong.

    Back to reference 9

  8. Engineering Fundamentals/Force and Power/Geometry, Mass, and Force

    Addendum 10. Sources and engineering context

    NASA Glenn’s weight-and-mass explanation distinguishes F = ma from W = mg. The NIST SI Units reference lists kilograms as an SI base unit and newtons as a derived unit. Those conventions are used here with g0 = 9.80665 m/s2 for the standard-gravity examples.

    The density conversion is from NIST SP 811, Appendix B, which lists slug per cubic foot to kilogram per cubic meter as 5.153 788 E+02; 0.00194032 is its reciprocal.

    Back to reference 10